(a)Define strain.
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A copper wire of length 4.0 m has a uniform cross-sectional area of 4.5 × 10⁻⁷ m². A tensile force of 18 N is applied to the wire. This causes the wire to extend by 1.4 mm up to its limit of proportionality.
(b)(i)Calculate the Young modulus of the wire.
A copper wire of length 4.0 m has a uniform cross-sectional area of 4.5 × 10⁻⁷ m². A tensile force of 18 N is applied to the wire, causing it to extend by 1.4 mm up to its limit of proportionality.
(b)(ii)On Fig. 4.1, draw a line to show how the stress varies with the strain for the wire up to its limit of proportionality.

A copper wire of length 4.0 m has a uniform cross-sectional area of 4.5 × 10⁻⁷ m² and a tensile force of 18 N is applied to it. A second copper wire has the same length as this wire but a larger diameter. Both wires are subjected to a tensile force of 18 N.
(c)By placing a tick (✓) in each row, complete Table 4.1 to compare the stress and strain of the two wires.