Nuclei of an isotope of copper (Cu) each have 29 protons and 37 neutrons. This isotope is a β⁻ emitter.
(a)State the nuclide notation in the form ᴬ_Z X for this nucleus of copper.
Nuclei of an isotope of copper (Cu) each have 29 protons and 37 neutrons. This isotope is a β⁻ emitter.
(a)State the nuclide notation in the form ᴬ_Z X for this nucleus of copper.
Nuclei of an isotope of copper (Cu) each have 29 protons and 37 neutrons; this isotope is a β⁻ emitter. The energy spectrum of the β⁻ radiation emitted by a sample of this isotope is shown in Fig. 7.1.
(b)(i)Use Fig. 7.1 to explain why other particles apart from the β⁻ particles must be emitted during this decay.

An isotope of copper with 29 protons and 37 neutrons is a β⁻ emitter, and the β⁻ particles are emitted with a continuous range of kinetic energies.
(b)(ii)State the name of the other particle emitted during the decay of this isotope.
An isotope of copper (Cu) whose nuclei each have 29 protons and 37 neutrons is a β⁻ emitter. The copper isotope decays to an isotope of zinc (Zn).
(b)(iii)Give the radioactive decay equation for this decay. Include the nucleon and proton numbers of all the particles involved.
9702/21/M/J/24Cambridge International AS & A Level Physics 9702 · May/June 2024 · Paper 2 variant 1 · Question 7